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(5x^2-20)-(4x-25)=180
We move all terms to the left:
(5x^2-20)-(4x-25)-(180)=0
We get rid of parentheses
5x^2-4x-20+25-180=0
We add all the numbers together, and all the variables
5x^2-4x-175=0
a = 5; b = -4; c = -175;
Δ = b2-4ac
Δ = -42-4·5·(-175)
Δ = 3516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3516}=\sqrt{4*879}=\sqrt{4}*\sqrt{879}=2\sqrt{879}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{879}}{2*5}=\frac{4-2\sqrt{879}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{879}}{2*5}=\frac{4+2\sqrt{879}}{10} $
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